x-4=0, x=4
y-3=0, y=3
z+5=0, z=-5

x^2/8+y^2/18+z^2/50=
16/8+9/18+25/50=3

How do I do this Loki

Again very easy problem
13-x= 5
X= 8
-14-y= -1
Y= -13
So initial point will be ( 8,-13)

(5^-1)^log(5^1/2) (1/4+1/8+...)=
(1/4+1/8+..)^-2=
(2)^-2=1/4

Sinx = 1/3

Cos x= 2√2/3

For 2nd quadrant only sin +ve

Sin2x = 4√2/9

Cos2x= -7/9

Tan2x = -4√2/7
😶

x^2-3x+1=0
x^2+1=3x
x+1/x=3

(x+1/x)^2=9
x^2+1/x^2=7
(x-1/x)^2+2=7
x-1/x=-sqrt(5)

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5x+1/2x=4
(5x+1/2x)^2=16
25x^2+5+1/4x^2=16
25x^2+1/4x^2=11
(5x-1/2x)^2+5=11
5x-1/2x=sqrt(6)

(5x-1/2x)(5x+1/2x)=
25x^2-1/(4x^2)=4sqrt(6)

5/13 Cos@ + 12/13sin@=1

Cos^2@ + sin^2@=1

It means sin@=12/13

1/cosx-sinx/cosx=1/sqrt(3)
sqrt(3)•(1-sinx)=cosx
sin^2(x)+cos^2(x)=1
->
3(1-2sinx+sin^2(x))+sin^2(x)=1
4sin^2(x)-6sinx+2=0
2sin^2(x)-3sinx+1=0
D=9-8=1

sinx=(3+1)/4=1 -> x=pi/2
sinx=(3-1)/4=0.5 -> x=30

=> secx•tanx=sinx/cos^2(x)=0.5/(3/4)=
2/3