Forwarded from Vicky NARCOTICS SSC CGL 2025 SELECTED
Forwarded from Deleted Account
1/x=a, 1/y=b, 1/z=c
5a^2+5b^2+5c^2-4ab-4ac-4ab=0
(2a-b)^2+(2b-c)^2+(2c-a)^2=0
=> 2a-b=2b-c=2c-a=0
1/x+1/y+1/z=0
5a^2+5b^2+5c^2-4ab-4ac-4ab=0
(2a-b)^2+(2b-c)^2+(2c-a)^2=0
=> 2a-b=2b-c=2c-a=0
1/x+1/y+1/z=0
Forwarded from Yogesh
Let x length of reactangle
Bd=ec=a-x/2
Triangle fec
√3:1:2
1------(a-x/2)
Ef-----√3(a-x/2)
Area=x*√3(a-x/2)
Differenciation with respect to x
√3x(0-1/2)+(a-x/2)(√3)=0
-x/2+a/2-x/2=0
X=a/2
Put area= a/2√3a/4
√3a^2/8=,half of equivilateral
De=24/2=12
Bd=ec=a-x/2
Triangle fec
√3:1:2
1------(a-x/2)
Ef-----√3(a-x/2)
Area=x*√3(a-x/2)
Differenciation with respect to x
√3x(0-1/2)+(a-x/2)(√3)=0
-x/2+a/2-x/2=0
X=a/2
Put area= a/2√3a/4
√3a^2/8=,half of equivilateral
De=24/2=12
Forwarded from C
n² = 48 + m²
(n - m)(n + m) = 48
13, 11
8,4
7,1
3 values
n = 1, 4, 11
(n - m)(n + m) = 48
13, 11
8,4
7,1
3 values
n = 1, 4, 11
Forwarded from Deleted Account
n^2+48=x^2
x^2-n^2=48
(x-n)(x+n)=48
48=1•48=3•16=12•4=6•8=24•2
(x-n)(x+n)=1•48
x-n=1
x+n=48 -> x=49/2
x-n=4
x+n=12 -> x=8, n=4
x-n=3
x+n=16 -> x=19/2
x-n=6
x+n=8 -> x=7, n=1
x-n=2
x+n=24 -> x=13, n=11
=> n=1; 4; 11
x^2-n^2=48
(x-n)(x+n)=48
48=1•48=3•16=12•4=6•8=24•2
(x-n)(x+n)=1•48
x-n=1
x+n=48 -> x=49/2
x-n=4
x+n=12 -> x=8, n=4
x-n=3
x+n=16 -> x=19/2
x-n=6
x+n=8 -> x=7, n=1
x-n=2
x+n=24 -> x=13, n=11
=> n=1; 4; 11