828 - (9 + 2*90) = 639

639/3 = 213

213 + 99 = 312

For 2^5

Check remainder of last 5 digits

11312 % 32

16

Solution please

Add ± 4x²

(2x)² - 2*2x*(1 - x²) + (1 - x²)²

(2x - 1 + x²) = 0

x = - 1 ± √2

Yogesh @astitwa batao Bhai plz__ yee

Let's
200=pa+5
120=pb+3
Pa*pb=195*117
P^2*a*b=5*39*13*9
=(39)^2*5*3
It can be in the form
=(13)^2*.......
(3)^2*....
Put p>5 so p can't be 3
39+13=52

Yogesh ise bhi ho sake to🙈

7a+2=6b+3=5c+4
9=5+4=6+3=7+2
596/9=. 9*66+2
66=9*7+3
7=9*0+7
So 596

SinAcosB : CosAsinB = 2 : 1

Sin(A-B) : Sin(A+B)= 1 : 3
Sinx : sinα = 1 : 3
Sinx = sinα /3
Dekhna @Unvanquishable

Sina*cosb=2cosa*SinB
Sin(a-b)=cosa*SinB
Sinx=cosa*SinB
Sin@=Sina*cosb+cosa*SinB
=3cosa*SinB
Sinx=sin@/3
Where@=alpha