Forwarded from CԍʟMᴀιɴs™(Adναиcє&Aяɪтнмεтιc) (Narendra Singh)
Forwarded from CԍʟMᴀιɴs™(Adναиcє&Aяɪтнмεтιc) (☆꧁༒Galaxy༒꧂☆)
Forwarded from Yogesh
2(c-b)x=c-b
X=1/2
A/4+c+b=0
A+4c+4b=0
A/4+b+c=0
A+4b+4c=0
Add. 2a+8c+8b=0
a+4b+4c=0
X=1/2
A/4+c+b=0
A+4c+4b=0
A/4+b+c=0
A+4b+4c=0
Add. 2a+8c+8b=0
a+4b+4c=0
Forwarded from Yogesh
Total number of 2 in the product of Frist 100 natural numbers
50+25+12+6+3+1=97
Eliminate those which are giving even power like
2^2 we have to take odd multiple
2^2(1,3,5,7,. Total 13)
Total power of 2. =13*2=26
2^3 with this we can take
2^1, 2^3 but 2^5*2^3>100
Power of 2 we took=4+6=10
Now 2^4( 2^0 already taken
(2^2. Taken)
(2^4. More than 100)
Odd multiple 2^4( 1. Taken already) mu
. (3 Yes)
(5, yes)
Power of 2= 5+3=8
2^5. ( 2^1 already ,2^3 greater>100)
Remaining power =97-(26+10+8)
=97-(44)= 53
50+25+12+6+3+1=97
Eliminate those which are giving even power like
2^2 we have to take odd multiple
2^2(1,3,5,7,. Total 13)
Total power of 2. =13*2=26
2^3 with this we can take
2^1, 2^3 but 2^5*2^3>100
Power of 2 we took=4+6=10
Now 2^4( 2^0 already taken
(2^2. Taken)
(2^4. More than 100)
Odd multiple 2^4( 1. Taken already) mu
. (3 Yes)
(5, yes)
Power of 2= 5+3=8
2^5. ( 2^1 already ,2^3 greater>100)
Remaining power =97-(26+10+8)
=97-(44)= 53