a³-b³/(a-b)³ = 157/3
a²+b²+ab / a²+b² -2ab = 157/3
(a+b) = x
x² - ab / x² - 4ab = 157/3
3x²-3ab = 157x²-628ab
154x² = 625ab
x² = 625 * 616/154 = 25² * 2²
x = 50

706*5-4*740=y
Y=570(youngest)

636*5=y+y+80+z
636*5=570*2+80+z
Z=3180-1220=1960
Initial salery of eldest brother=4*740-1960
=2960-1960=1000

Decreased by 34
34*5=170
Salary of youngest=740-170
=570
Now salary of eldest after a leave=570+80=650
Overall average reductions
706-636=70
70*5=350 total reduction in salary of eldest
Old salary=350+650=1000

38*78 - 34x = 100(38-x)
2964 - 34x = 3800-100x
66x = 836
x ~ 12.67
Means max 12

Maximum failed
Means minimum pass
Minimum pass means
Jo pass h unke jyda number ho
Maximum 100
+22 deviation
Failed hoga 34 pe
78-34=-44 deviation
22*26=44*13
But 26+13=39
So possible combinations
22*(24+0)=44*12
Means 2 aise h jinke 78 exact number h

Y krna bhai

Two digit nos :

xy + (x + y) = 10x + y

y = 9

x = (1 to 9)

So 9


Three Digits nos :

xyz + (x + y + z) = 100x + 10y + z

xyz = 9(11x + y)

Hit n trial

No solution

So only 9.

Let no.

100x + 10y + z (where x > y > z)

Since divisible by 10 so z = 0

100x + 10y

New no.

100y + 10x (Divisible by 10)


100x + 10y - (100y + 10x)

90(x - y) % 40

(x - y) should be divisible by 4

(9, 1), (9, 5)

(7, 3)

(6, 2)

(5, 1)

A

k + 4 = 7p

k = 7p - 4

(7p - 4 + 2n) is divisible by 7

(2n - 4) is divisible by 7

n = 9