HCF & LCM Best Pdf ( Almost All Types Covered )
(Bilingual)

By - SHUBHAM KUMAR ( TA IN CBDT )

Video Solution - https://youtu.be/trqpDxpEZuk

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x litres - alchohol, y - water.

18l —- 3/4
60l —- 2/5.

60l-18l —— 75-40%
42l => 35%
6l => 5%

Then, with every 6 liters of water added, the amount of alcohol decreases by 5%. So to find the amount of the mixture, we find the amount of water when the amount of alcohol is 0:

40%:5=8 => 8•6=48l

(60+48)l —- 0%
The amount of mixture is 108l.

Then, if we 0litres of mixture is taken out and replaced with water, percentage of alcohol:
108l:6=18

0l ——- 18•5%=90%.

Then, X=108•0.9=97.2litre

#SSC CHSL 2021 QUANT PRACTICE SET 2

Video Solution - https://youtu.be/KdepO2gLxsw

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