Electric Dipole Quick Review 🤗
🔻The energy of electric dipole is given by U = – p.E.
🔻The energy of a magnetic dipole is U = – μ .B C.
🔻Electric Charge : Q = ± ne (e = 1.60218 × 10-29 C)
🔻SI unit of Electric Charge is Coulomb (C)
🔻Coulomb’s Law : Electrostatic Force (F) = k[q1q2/r2] and,
In Vector Form :
→F=k(q1q2)×→r/r3
Where, q1 and q2 = Charges on the Particle,
r = Separation between them,
→r = Position Vector,
k = Constant = 14πϵ0=8.98755×109Nm2C2
🔻Electric Current :
The current at Time t : i=limΔt→0 ΔQ/Δt= dQ/dT
Where Δ Q and Δ T = Charges crosses an Area in time Δ T
SI unit of Current is Ampere (A) and 1A = 1 C/s
🔻Average current density:
→j=Δi/Δs
j=limΔs→0 Δi/Δs=di/dS ,
j=Δi/ΔScosθ
Where, Δ S = Small Area,
Δ i = Current through the Area Δ S,
P = Perpendicular to the flow of Charges,
θ = Angle Between the normal to the Area and the direction of the current.
🔻Kirchhoff’s Law:
Law of Conservation of Charge: I3 = I1 + I2
Resistance
🔻Resistivity : ρ(T)=ρ(T0)[1+α(T−T0)]
R (T) =R (T0) [1+α (T−T0)]
Where, ρ (T) and ρ (T0) = Resistivity at Temperature T and T0 respectively,
α = Constant for given material.
🔻Lorentz Force :
→F=q[→E+(→v×→B)]
Where, E = Electric Field,
B = Magnetic Field,
q = Charge of Particle,
v = Velocity of Particle.
🔻Magnetic Flux:
Magnetic Flux through Area dS = ϕ=→B⋅d → S= B⋅dS Cos θ
Where, d→S = Perpendicular vector to the surface and has a magnitude equal to are Ds,
→B = Magnetic Field at an element,
θ = Angle Between →B and d→S,
SI unit of Magnetic Flux is Weber (Wb).
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🔻The energy of electric dipole is given by U = – p.E.
🔻The energy of a magnetic dipole is U = – μ .B C.
🔻Electric Charge : Q = ± ne (e = 1.60218 × 10-29 C)
🔻SI unit of Electric Charge is Coulomb (C)
🔻Coulomb’s Law : Electrostatic Force (F) = k[q1q2/r2] and,
In Vector Form :
→F=k(q1q2)×→r/r3
Where, q1 and q2 = Charges on the Particle,
r = Separation between them,
→r = Position Vector,
k = Constant = 14πϵ0=8.98755×109Nm2C2
🔻Electric Current :
The current at Time t : i=limΔt→0 ΔQ/Δt= dQ/dT
Where Δ Q and Δ T = Charges crosses an Area in time Δ T
SI unit of Current is Ampere (A) and 1A = 1 C/s
🔻Average current density:
→j=Δi/Δs
j=limΔs→0 Δi/Δs=di/dS ,
j=Δi/ΔScosθ
Where, Δ S = Small Area,
Δ i = Current through the Area Δ S,
P = Perpendicular to the flow of Charges,
θ = Angle Between the normal to the Area and the direction of the current.
🔻Kirchhoff’s Law:
Law of Conservation of Charge: I3 = I1 + I2
Resistance
🔻Resistivity : ρ(T)=ρ(T0)[1+α(T−T0)]
R (T) =R (T0) [1+α (T−T0)]
Where, ρ (T) and ρ (T0) = Resistivity at Temperature T and T0 respectively,
α = Constant for given material.
🔻Lorentz Force :
→F=q[→E+(→v×→B)]
Where, E = Electric Field,
B = Magnetic Field,
q = Charge of Particle,
v = Velocity of Particle.
🔻Magnetic Flux:
Magnetic Flux through Area dS = ϕ=→B⋅d → S= B⋅dS Cos θ
Where, d→S = Perpendicular vector to the surface and has a magnitude equal to are Ds,
→B = Magnetic Field at an element,
θ = Angle Between →B and d→S,
SI unit of Magnetic Flux is Weber (Wb).
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➪ Vector & Scalars Short Notes 🗒️
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Kinetic Theory Of Gases 🥰
NCERT Notes ⚡
All Concepts Clear ✔️
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Which of the reactions will need the maximum amount of energy?
Anonymous Quiz
22%
Na → Na+ + e–
29%
Ca+ → Ca++ + e–
24%
K+ → K+ ++ e–
24%
C2+ → C3+ + e–
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If the initial velocity of the object is 2m/s and the acceleration is 4 ms⁻² find the distance for the n=10m?
Anonymous Quiz
43%
40 m
34%
45 m
17%
55 m
6%
65 m
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Circular Motion Short Notes ⚡
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