⚡ElectroMagnetic Induction (EMI)
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The forces responsible for a body regaining its shape after removal of deforming forces are ________
Anonymous Quiz
22%
gravitational forces between atoms
39%
electromagnetic forces between atoms
18%
nuclear forces within an atom
21%
combination of gravitational & nuclear forces between atoms
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Which of the following quantities have the same S.I. unit as that of modulus of elasticity?
Anonymous Quiz
38%
Energy per unit volume
39%
Force per unit length
13%
Energy
10%
Change in length
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➪ Biological Classification 🙌
✅ Full Chapter NCERT Based Notes
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Calculate the velocity of the light ray in the medium, if the critical angle for TIR from medium to the vacuum is 30°.
Anonymous Quiz
16%
2 x 108 m/s
44%
1.5 x 108 m/s
23%
0.75 x 108 m/s
17%
3 x 108 m/s
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Which of the following is the combination that is used in the formation of achromatic lenses?
Anonymous Quiz
29%
1 convex and 1 plane mirror
29%
2 convex lenses
37%
1 convex and 1 concave lens
5%
2 concave lenses
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How does magnifying power change for an objective lens if the focal length of the objective lens is increased?
Anonymous Quiz
30%
The microscope will decrease but for the telescope, it will increase
43%
The microscope will increase but for the telescope, it decreases
21%
The microscope and telescope will increase
6%
The microscope and telescope will decrease
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What is the magnification produced by the plane mirror?
Anonymous Quiz
25%
0
43%
+1
10%
-1
22%
0 to infinity
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The image formed by the convex mirror is 1/n times the object and has a focal length f. What is the distance of object from the mirror?
Anonymous Quiz
26%
(n + 1)f
37%
(n – 1)f
30%
{(n+1)/n}f
7%
{(n−1)\n}f
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Whole Physics Formulas in 4 Pages ⚡
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Electric Dipole Quick Review 🤗
🔻The energy of electric dipole is given by U = – p.E.
🔻The energy of a magnetic dipole is U = – μ .B C.
🔻Electric Charge : Q = ± ne (e = 1.60218 × 10-29 C)
🔻SI unit of Electric Charge is Coulomb (C)
🔻Coulomb’s Law : Electrostatic Force (F) = k[q1q2/r2] and,
In Vector Form :
→F=k(q1q2)×→r/r3
Where, q1 and q2 = Charges on the Particle,
r = Separation between them,
→r = Position Vector,
k = Constant = 14πϵ0=8.98755×109Nm2C2
🔻Electric Current :
The current at Time t : i=limΔt→0 ΔQ/Δt= dQ/dT
Where Δ Q and Δ T = Charges crosses an Area in time Δ T
SI unit of Current is Ampere (A) and 1A = 1 C/s
🔻Average current density:
→j=Δi/Δs
j=limΔs→0 Δi/Δs=di/dS ,
j=Δi/ΔScosθ
Where, Δ S = Small Area,
Δ i = Current through the Area Δ S,
P = Perpendicular to the flow of Charges,
θ = Angle Between the normal to the Area and the direction of the current.
🔻Kirchhoff’s Law:
Law of Conservation of Charge: I3 = I1 + I2
Resistance
🔻Resistivity : ρ(T)=ρ(T0)[1+α(T−T0)]
R (T) =R (T0) [1+α (T−T0)]
Where, ρ (T) and ρ (T0) = Resistivity at Temperature T and T0 respectively,
α = Constant for given material.
🔻Lorentz Force :
→F=q[→E+(→v×→B)]
Where, E = Electric Field,
B = Magnetic Field,
q = Charge of Particle,
v = Velocity of Particle.
🔻Magnetic Flux:
Magnetic Flux through Area dS = ϕ=→B⋅d → S= B⋅dS Cos θ
Where, d→S = Perpendicular vector to the surface and has a magnitude equal to are Ds,
→B = Magnetic Field at an element,
θ = Angle Between →B and d→S,
SI unit of Magnetic Flux is Weber (Wb).
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🔻The energy of electric dipole is given by U = – p.E.
🔻The energy of a magnetic dipole is U = – μ .B C.
🔻Electric Charge : Q = ± ne (e = 1.60218 × 10-29 C)
🔻SI unit of Electric Charge is Coulomb (C)
🔻Coulomb’s Law : Electrostatic Force (F) = k[q1q2/r2] and,
In Vector Form :
→F=k(q1q2)×→r/r3
Where, q1 and q2 = Charges on the Particle,
r = Separation between them,
→r = Position Vector,
k = Constant = 14πϵ0=8.98755×109Nm2C2
🔻Electric Current :
The current at Time t : i=limΔt→0 ΔQ/Δt= dQ/dT
Where Δ Q and Δ T = Charges crosses an Area in time Δ T
SI unit of Current is Ampere (A) and 1A = 1 C/s
🔻Average current density:
→j=Δi/Δs
j=limΔs→0 Δi/Δs=di/dS ,
j=Δi/ΔScosθ
Where, Δ S = Small Area,
Δ i = Current through the Area Δ S,
P = Perpendicular to the flow of Charges,
θ = Angle Between the normal to the Area and the direction of the current.
🔻Kirchhoff’s Law:
Law of Conservation of Charge: I3 = I1 + I2
Resistance
🔻Resistivity : ρ(T)=ρ(T0)[1+α(T−T0)]
R (T) =R (T0) [1+α (T−T0)]
Where, ρ (T) and ρ (T0) = Resistivity at Temperature T and T0 respectively,
α = Constant for given material.
🔻Lorentz Force :
→F=q[→E+(→v×→B)]
Where, E = Electric Field,
B = Magnetic Field,
q = Charge of Particle,
v = Velocity of Particle.
🔻Magnetic Flux:
Magnetic Flux through Area dS = ϕ=→B⋅d → S= B⋅dS Cos θ
Where, d→S = Perpendicular vector to the surface and has a magnitude equal to are Ds,
→B = Magnetic Field at an element,
θ = Angle Between →B and d→S,
SI unit of Magnetic Flux is Weber (Wb).
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