KIMYO ๐Ÿ”— ABDIYEV
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Kimyo fani bo'yicha:
- Masalalar va ularning sodda yechimlari
- Nazariy ma'lumotlar
- Qiziqarli faktlar

You-tube kanal ๐Ÿ‘‡
https://youtube.com/channel/UCAWrT8AgWLiuwR5R0AubEFw
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Ushbu grafikdan foydalanib, SO2 ning
yonish reaksiyasi tezligini (mol/lโˆ™sek) aniqlang. 2SO2 + O2 โ†’ 2SO3
A) 0,1 B) 0,4 C) 0,3 D) 0,2

/// ABDIYEV OสปQUV KURSI ///
Quyidagi grafik jadvaldan foydalanib uglerod II oksidning yonish reaksiyasining tezligini (mol/lโˆ™sek) aniqlang. 2CO + O2 = 2CO2
A) 0,1 B) 0,2 C) 0,3 D) 0,4

/// ABDIYEV OสปQUV KURSI ///
Quyidagi grafik jadvaldan foydalanib
amiakning xlor atmosferasida yonish
reaksiyasining tezligini (mol/lโˆ™sek) aniqlang. 2NH3 + 3Cl2 = N2 + 6HCl
A) 0,1 B) 0,2 C) 0,3 D) 0,4

/// ABDIYEV OสปQUV KURSI ///
Grafikka asoslanib S (q) + O2 (g) = SO2 (g) reaksiyasining muvozanat konstantasini (Km) aniqlang.
A) 1 B) 1,5 C) 2,5 D) 3

@Abdiyevschool
๐Ÿ‘1
Grafikka asoslanib S (q) + O2 (g) = SO2 (g) reaksiyasining dastlabki tezligini (mol/lโˆ™sek) aniqlang. ( k=0,8 )
A) 0 mol/lโˆ™sek
B) 4 mol/lโˆ™sek
C) 1,6 mol/lโˆ™sek
D) 4,8 mol/lโˆ™sek

@Abdiyevschool
Grafikka asoslanib 2SO2 (g) + O2 (g) = 2SO3 (g) reaksiyasining muvozanat konstantasini (Km) aniqlang.
A) 16/3 B) 4/3 C) 16/6 D) 1

@Abdiyevschool
๐Ÿ‘1
Grafikka asoslanib 2SO2 (g) + O2 (g) = 2SO3 (g) sistemada muvozanat qaror topgandan keyingi
tezligini (mol/lโˆ™sek) aniqlang. ( k = 0,8 ) A) 3 B) 2 C) 3,2 D) 2,4

@Abdiyevschool
Grafikka asoslanib N2 (g) + 3H2 (g) = 2NH3 (g) reaksiyasining H2 boโ€™yicha oโ€™rtacha tezligini (mol/lโˆ™sek) aniqlang. A) 0,03 B) 0,02 C) 0,01 D) 0,1

@Abdiyevschool
Kimyoni
(Barcha fanni) o'rganishadi ko'p uchraydigan xatolar: (o'zimni fikrlarim)
1. O'zingni boshqalarga solishtirish.
Bu bilan sen faqat va faqat yutqazasan. Boshqalar menga nisbatan yaxshi bilimli men esa unaqa emasman degan fikrdan qochish kerak.
O'zingni boshqalarga emas, oโ€˜zingni oldingi holatingga nisbatan solishtir.

2. Shoshqaloqlik.
Shoshilmaslik kerak. Bu senga katta yuklamalar yuklaydi. Oโ€˜zingga haddan ortiq talabchan boโ€˜lma. Oโ€˜rganish uzoq muddatli protses, unga ko'p vaqt ketadi.
Bu xuddi uzoq masofaga chiqqan yo'lovchiga o'xshaydi. Birinchi kunda hamma ovqati va suvini tugatib qo'ysa, yo'lni oxirigacha bora olmaydi. Shunday ekan muhimi ishtiyoqni saqlab turish. Oz ozdan ammo davomli (davriy) qoidasiga amal qil.

Davomi bor...

@Abdiyevschool
๐Ÿ‘29โšก7
Diatomic Elements

Always form groups of two. You never find just one alone by itself. Br2, I2, N2, Cl2, H2, O2, F2

Ikki atomli elementlar(moddalar)

Har doim ikki atomli ko'rinishida bo'ladi. Hech qachon bir atomli ko'rinishda uchramaydi.
Br2, I2, N2, Cl2, H2, O2, F2

@Abdiyevschool
๐Ÿณ7๐Ÿ‘€3โค2๐Ÿ‘2๐Ÿ”ฅ1
Container H below has twice the volume of container G. How will the pressure in the containers compare? Explain your reasoning.

Quyida berilgan H idish hajmi G idishining hajmidan ikki baravar katta. Idishlardagi bosim qanday taqqoslanadi? Fikringizni tushuntirib bering.

@Abdiyevschool
๐Ÿ‘5๐Ÿ”ฅ2
How do the pressures in the two containers compare? compare? Be sure to explain your answer.

Ikki idishdagi bosimlar qanday taqqoslanadi? solishtiring?

@Abdiyevschool
๐Ÿ‘4๐Ÿ‘Œ1
Shown below are four different containers (C, D, E, and F), each with the same volume and at the same temperature. How do the pressures of the gases in the containers compare?

Quyida har biri, bir xil hajmga va bir xil haroratga ega bo'lgan to'rt xil konteyner (C, D, E va F) ko'rsatilgan. Idishlardagi gazlarning bosimlari qanday taqqoslanadi?

@Abdiyevschool
๐Ÿ”ฅ2๐Ÿ‘1
Consider containers J and L below. Container L has twice the volume of container J. Container J is at a temperature of 100 K, and container L is at 200 K. How does the pressure in container J compare with that in container L? Include an explanation as part of your answer

Quyidagi J va L konteynerlarini ko'rib chiqing. L idishdan J idishning hajmi ikki baravar kichik. J idishda haroratda100 K, L idish esa 200 K da. J idishdagi bosim L idishdagi bosim bilan qanday taqqoslanadi? Javobingizni izohlang.

@Abdiyevschool
๐Ÿ’ฏ2๐Ÿ‘1๐Ÿ”ฅ1๐Ÿ‘1
Forwarded from Biologiya | KENJAYEV.O (ะ‘ะ˜ะžะ›ะžะ“)
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KIMYOVIY BOG'LANISH, KP, GIBRIDLANISH.pdf
817.7 KB
KIMYOVIY BOG'LANISH, K/P, GIBRIDLANISH MAVZULARIDAN MUSTAQIL TAKRORLASH UCHUN NAZARIY MA'LUMOTLAR BAZASI.
// ABDIYEV O'QUV KURSI ABITURIYENTLARI UCHUN //
Kimyo_uzb.pdf
119.7 KB
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๐Ÿ“šFan: Kimyo
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