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Keling!!! Kimyoni birgalikda Γ³rganamizπŸ”₯
Π”Π°Π²Π°ΠΉΡ‚Π΅!!! Π˜Π·ΡƒΡ‡Π°Π΅ΠΌ вмСстС Π₯имиюπŸ”₯
ustoz: Bunyod Raxmanov
Bog'lanish πŸ”— @ChemOfficer_bot
Bog'lanish πŸ”— @ProChem
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UNIVERSAL KIMYO
5.15K subscribers
UNIVERSAL KIMYO
πŸ” πŸ” πŸ” πŸ” πŸ” 
πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 
Nega aynan Hg metallar ichida suyuq, xatto massasi og'ir bo'lsada⁉️
Keling shu savolga ilmiy asosda javob beramiz. Simob 6-davrning IIB guruhida joylashgan bo'lib, elektron konfiguratsiyasi eng barqaror holda, ya'ni orbitallari to'liq elektronlar bilan to'lgan. Ayniqsa, 4f¹⁴ orbitallari to'liq elektronlar bilan qoplanishi alohida ahamiyatli bo'lib, orbitallarning yadro bilan potensialini (markazga intilma kuchini) oshirib beradi. Natijada simob atomi energetik barqarorlikka erishgan bo'lib, orbitallardagi elektronlar atom yadrosi bilan mustahkam bog'langan. Bilamizki, metall kristall panjara hosil bo'lishida atomlar panjara bo'shliqlariga elektronlar joylashtirishi natijasida atomlararo o'zaro umumiy barqaror sitema hosil qiladi. Ammo, simob shundog'am atom (xususiy) holida barqaror sistema holiga kelgan. Energetik afzallik nuqtai nazardan simobda atomlararo kristall panjaralar oraliqlariga elektronlarni joylashtirib umumiy sistema hosil qilgandan ko'ra, o'zi alohida atom (xususiy) holida orbitallarida elektronlarni saqlash optimalligi aniqlangan. Natijada, atomlararo bog' zaifligi sabab, barqaror kristall panjara ham shakllanmaydi.
Xulosa: simobning boshqa metallardan farqli ravishda n.sh.da ham suyuq metall bo'lishining asosiy sababi, atom (xususiy) sifatida barqarorligi atomlararo (umumiy) kristall panjara barqarorligidan ustunligidir.
tahlilchi: ustoz Bunyod Raxmanov

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
kanalπŸ”— @ChemOfficer
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❀4πŸ”₯2πŸ‘1
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​2️⃣4οΈβƒ£πŸ†š3️⃣0️⃣

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
kanalπŸ”— @ChemOfficer
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πŸ‘1πŸ˜‡1
478 viewsChemOffice, 
πŸ…°οΈ 24βœ… 6πŸ…±οΈ 30βœ… 3
πŸ“yechim beraman
UNIVERSAL KIMYO
ChemOffice
​2️⃣4οΈβƒ£πŸ†š3️⃣0️⃣ ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov kanalπŸ”— @ChemOfficer kanalπŸ”— @olympic_uz_ru_en
πŸ” πŸ” πŸ” πŸ” πŸ” πŸ” 

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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❀3πŸ”₯3
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πŸ–₯ Nihoyat ulkan hajmli kitobni bugun tΓ²liq yakunladim. Avvalo taqdirni belgilovchi bu yaratguvchi! Undan keyin esa qΓ²rqmasdan oldindan shuni ayta olamanki: eng ilmiy kuchli, eng ilmiy sifatli, eng yangilikka boy, eng ishonchli, eng dolzarb mavzularni ochgan, eng keng mavzular qamroviga ega nazariy kuchli kitob qaysi deyilsa, aynan UNIVERSAL KIMYO deyiladi. Bu oddiy testlar tΓ²plami kitobi emas, bu Γ²rta darajadagi nazariy kitob emas, bu haqiqiy ilmiy ijod manbai. Nasib ertaga nashriyotga boraman. Xullas asl ilmni qadrlovchi hurmatli ilm ahli,... bu ilmiy ijodiy ishim mendan kΓ²ra sizlarga va kelajak avlodlaringizga juda katta foydasi tegadi.

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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πŸ”₯11❀6πŸ˜‡5🀝1
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🧠miyani charxlaymizβš”οΈ
βœ”οΈyechimingizni tahlil guruhida bildiring

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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πŸ” πŸ” πŸ” πŸ” πŸ” πŸ” 

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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...tabiat shunday go'zalki, xech qanday sun'iy go'zallik uni o'rnini bosa olmaydi, sizlargada ulashgim keldi

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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😍7❀4
417 viewsπ‚π‘πžπ¦πŽπŸπŸπ’πœπž, 
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⌨️⌨️6οΈβƒ£βŒ¨οΈβŒ¨οΈβŒ¨οΈβŒ¨οΈβŒ¨οΈ

βœ”οΈjavobingizni tahlil guruhida bildiring

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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πŸ‘Œ1πŸ€—1
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βŒ¨οΈπŸ”£βŒ¨οΈβŒ¨οΈβŒ¨οΈβŒ¨οΈ6️⃣
kanal faol a'zosi Γ²qigan "ilmiy" adabiyoti asosida men tashlagan nazariy savolga e'tiroz bildiribdiπŸ’¬

⚠️siz tashlagan rasmga qarasak etanolning nitrolanishida HNO3 ning OH qismi deyilgan, lekin aslida H qismi bilan reyaksiya beradiku, mana sizga fakt!

πŸ‘€mana ayrim kitoblar qanday qip-qizil xato ma'lumot beradi, e'tiborli bo'ling, aslo bir kitob asosida tez xulosa chiqarmang!

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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πŸ‘Œ1
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πŸ˜‚βŒ¨οΈβŒ¨οΈβŒ¨οΈβŒ¨οΈβŒ¨οΈβŒ¨οΈ
Reaksiya nukleofil reaksiyaning Sn2 mexanizmida borib, bunda kislotali muhit katta rΓ²l Γ²ynaydi. Protolitik nazariyaga asosan, kuchli kislota degani, demakki uning tarkibida kuchsiz asos bor degani va shu tufayli barqaror birikma (H2O) hosil qilish uchun Γ²ziga proton (H+) qabul qiladi va natijada NO2+ ionini hosil bΓ²ladi:
HO–NO2 + H+ β€”> NO2+ + H2O
Spirtdagi O atomi Δ“ ga tΓ²yingan bΓ²lib, musbat zaryadni izlaydi (nukleofil). Natijada spirt va NO2+ ioni Sn2 mexanizmni yaratadi:

H H
| |
C2H5O: + NO2+ β€”> [C2H5O:NO2]+

H
|
[C2H5O:NO2]+ β€”> C2H5NO2 + H+

Xulosa: spirtlarning nitrolanish reaksiyasida spirtlardan –H, nitrat kislotadan esa –OH ishtirok etadi.

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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πŸ”₯4❀2
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To'g'ri javobβœ…
Anonymous Quiz
37%
metiletilpropilamin
20%
etilmetilpropilamin
20%
N-metil-N-etilpropanamin-1
24%
N-etil-N-metilpropanamin-1
πŸ‘3
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✍2❀1
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To'g'ri javobβœ…
Anonymous Quiz
37%
metiletilpropilamin
25%
etilmetilpropilamin
22%
N-metil-N-etilpropanamin-1
17%
N-etil-N-metilpropanamin-1
🀝4❀1
102 voters506 viewsπ‚π‘πžπ¦πŽπŸπŸπ’πœπž, 
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gr πŸ†š g

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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🧠miyani charxlaymizβš”οΈ
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❀️‍πŸ”₯❀️‍πŸ”₯❀️‍πŸ”₯πŸ’™πŸ’™πŸ’™
Assalomu aleykum hurmatli ilm ahli!
Agar kimda davriy jadvalning metallar, metallmaslar, yarim metallar va amfoter metallar ajratib ko'rsatilgan hamda NEM qiymati berilgan tiniq varianti bo'lsa iltimos! shaxsiyim (Π»ΠΈΡ‡ΠΊΠ°ΠΌ) ga tashlab bersangiz, kitob muqovasining 1-bet ichki qismiga joylaymiz. Eruvchanlik jadvali bo'lsa uni ham tashlab beravering, balki qulaylik uchun ost-ust qilib joylarmiz. O'zimizda ham bor variantlar, balki sizda bori yanada zo'rdir. Kitobga sizning ham savobli ulushingiz qo'shilsinπŸ˜‡

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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πŸ–₯ qaranglar hurmatli ilm ahli: tartib raqami metallmaslar kvadratga, amfoter metallarniki yarim aylana va NEM berilgan zo'r DJ bor edi, shuni izlayapman, ham soddagina, ham qulay edi. Shuni topsak juda zo'r bo'lardi.
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536 viewsπ‚π‘πžπ¦πŽπŸπŸπ’πœπž,