UNIVERSAL KIMYO
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Keling!!! Kimyoni birgalikda Γ³rganamizπŸ”₯
Π”Π°Π²Π°ΠΉΡ‚Π΅!!! Π˜Π·ΡƒΡ‡Π°Π΅ΠΌ вмСстС Π₯имиюπŸ”₯
ustoz: Bunyod Raxmanov
Bog'lanish πŸ”— @ChemOfficer_bot
Bog'lanish πŸ”— @ProChem
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ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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π‚π‘πžπ¦πŽπŸπŸπ’πœπž
Ozon molekulasidagi kislorod atomlarining oksidlanish darajalarini chapdan Γ²ngga tartibda aniqlang. πŸ”€ –2; +3; –1 πŸ”€ –2; +4; –2 πŸ”  0; +1; –1 πŸ”  0; +2; –2 πŸ”  0; 0; 0 βœ”οΈjavobingizni tahlil guruhida bildiring ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov kanalπŸ”— @ChemOfficer kanalπŸ”—β€¦
πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 

πŸ’ Oxidation state β€” oksidlanish daraja (OD)
πŸ’ Formal charge β€” formal zaryad (FZ)

πŸ”ΉOddiy moddalardagi atomlarning OD qiymatlari doimo 0 ga teng deb qabul qilingan.
πŸ”ΊOddiy moddalardagi atomlarning FZ qiymatlari atomlardagi elektronlarning butun molekula (struktur birlik) bo'yicha taqsimlanishiga asosan hisoblab topiladi.

⚠️eslatma: OD qiymati kelib chiqishi kimyoviy birikmadagi atomlarning NEM farqiga bog'liq bo'lsa, FZ NEM farqiga umuman bog'liq emas!

⌨️6οΈβƒ£βŒ¨οΈβŒ¨οΈ
FZ muhim mavzusi bizning darslik yoki qo'llanmalarga kirib kelganmi? β€” yo'q. Ammo kamina kitobida mukammal yoritilgan (kitobimni olganlardan so'rang). Bir ikki asl ilm-fanni ko'tara olmaydigan tanqidchilar gapi qulog'imga chalinganda: "bu kitobda DTM ga kiritilmagan mavzular ham bor, ular bizga kerak emas" - emish. Unda marhamat, o'quvchi-o'rganuvchilarga tushuntiring endi: nega 99,9% o'rgatuvchi-o'rganuvchilar formal zaryad qiymatini oksidlanish daraja deb xato ilm olayotganini yoki farqini tushuntira olmayotganini?! Xorij adabiyotlarida bilingki OD bilan bir qatorda FZ ham ko'p ishlatiladi. OD ularda asosan qachon ishlatiladi bilasizmi, kompleks murakkab birikmalarda, ya'ni birlamchi (primary) va ikkilamchi (secondary) valentliklarni aniqlashda.


ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanalπŸ”— @olympic_uz_ru_en
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πŸ” πŸ” πŸ” πŸ” πŸ” πŸ” 
πŸ”Έtest qoraqalpoq tilidaπŸ–₯
πŸ”ΈMS imtihonida tushgan rasmiy masalalar

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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kanalπŸ”— @olympic_uz_ru_en
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✴️DOLZARB SAVOL✴️
Asosiy guruh kimyoviy elementlarining maximal valentligi guruh tartib raqamiga teng (istisno, N, O, F ) β€” desak, to'g'rimi❓

✍🏻Fikringizni tahlil guruhida bildirishingiz mumkin

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
kanal
πŸ“’ @ChemOfficer
kanal
πŸ“’
@olympic_uz_ru_en
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πŸ” πŸ” πŸ” πŸ” πŸ” βŒ¨οΈβŒ¨οΈβŒ¨οΈβŒ¨οΈβŒ¨οΈβŒ¨οΈ
Kovalent bog' (KB)β€” atom orbitallari o'rtasida umumiy elektron juftlar hisobiga hosil bo'ladigan bog'dir. KB asosan ikki shaklda hosil bo'ladi.
1️⃣. Almashinadigan kovalent bog' ("sharing", "ΠΎΠ±ΠΌΠ΅Π½") AKB β€” har bir atom orbitallari o'rtasida toq elektronlarning o'zaro juftlashishidir.
2️⃣. Koordinatsion kovalent bog' ("dative", "donor-acceptor") KKB β€” bir atom orbitalidagi tayyor e juftning ikkinchi atomning bo'sh orbitaliga qo'yishidir.

...nima uchun KB ning asosiy ta'riflarini takrorlab oldik, hozir tushunib yetamiz. Asosiy guruh kimyoviy element (KE) larining guruh tartib raqami, bu uning valent elektron (VE) lar sonini anglatadi (ya'ni, aslida valentligini emas!). Bu VE lar sonining KB hosil qilish imkoniyati orbital sig'imiga bog'liq. Masalan, II davrdagi Li, Be, B, C - KE lari VE larining barchasi KB hosil qilish imkoniyati mavjud, chunki yetarli (1s+3p=4 orbital) orbital mavjud. Ayni shu davrdagi N, O, F - KE lari KB hosil qilishda VE larining maximal ishtiroki cheklangan. Sababi, yuqorida yozilganidek II davrda orbital sig'imi jami 4 ga teng. Shu tufayli ham bu 3 ta KE lar ham maximal IV valentlikni namoyon etishi mumkin (O va F nazariy jihatdan). Keyingi davrlarda orbital sig'imi ortishi ( bo'sh d, f - orbitallar) natijasida, KE larning barcha VE lari ishtirok etish imkoniyati bo'ladi. Masalan, maximal valentlik hosil qilish uchun P β€” 3s1 3p3 3d1, S β€” 3s1 3p3 3d2, Cl β€” 3s1 3p3 3d3 orbitallaridan foydalanadi. Endi diqqatimizni boshqa joyga qaratamiz...deylik, Be ning VE soni 2 ga teng, bu degani uning maximal valentligi II mi β€”?
Xaβœ… β€” AKB bo'yicha bu to'g'ri (bu ilmiy tilda asosiy "primary", "основной" -valentlik deyiladi). Masalan, BeH2, BeO, BeCl2, BeSO4 (II) va hk.
Yo'q❌ β€” KKB bo'yicha bu xato (bu ilmiy tilda ikkilamchi "secondary", "Π²Ρ‚ΠΎΡ€ΠΈΡ‡Π½Ρ‹ΠΉ" -valentlik deyiladi). Masalan, [Be2H4] (III), Na2[BeCl4] (IV), [Be(H2O)4]SO4 (IV) va hk.
...yoki boshqa misollar Si β€” SiO2 (IV), K2[SiF6] (VI); P β€” P2O5 (V), H[PCl6) (VI) va hk.

Xulosa: guruh tartib raqami bu asosiy guruh KE ning valent elektron sonini bildirib, orbital sig'imidan kelib chiqqan holda maximal valentlik tushunchasida AKB bo'yicha asosiy valentligini namoyon etishi mumkin, ammo KKB bo'yicha ikkilamchi valentlikni namoyon etishda bu o'zini oqlamaydi.

ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanalπŸ”— @olympic_uz_ru_en
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ustozπŸ‘¨πŸ»β€πŸ« Bunyod Raxmanov
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