UNIVERSAL KIMYO
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Keling!!! Kimyoni birgalikda Γ³rganamizπŸ”₯
Π”Π°Π²Π°ΠΉΡ‚Π΅!!! Π˜Π·ΡƒΡ‡Π°Π΅ΠΌ вмСстС Π₯имиюπŸ”₯
ustoz: Bunyod Raxmanov
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3οΈβƒ£πŸ†š4️⃣
yuqorida berilgan testlardan qay birining yechimi siz uchun muhimπŸ“
πŸ’»atigi 4 taπŸ”ˆqolibdi
50+ boΚ»lsa 1 ta mujmal masala yechimi, 100+ boΚ»lsa 2 ta mujmal masala yechimi ham beriladi
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πŸ“Šovozlar soni 50+ bΓΆlibdi, va'daga muvofiq yechim beraman
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πŸ” πŸ” πŸ” πŸ” πŸ” πŸ” 

⚜️MILLIY SERTIFIKAT⚜️ maxsus guruhida tahlil qilinayotgan testlardan
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ustoz✍️ Bunyod Raxmanov
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Bronza asosini Cu va Sn tashkil qilsa, bu ikki metall qotishmasining hosil bo'lishi qanday jarayon❓

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πŸ” πŸ”€πŸ” πŸŸ’πŸ”€
πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 

πŸ”₯UNIVERSAL KIMYOπŸ”₯
πŸ’ UMUMIY
πŸ’ ANORGANIK
πŸ’ ORGANIK
πŸ’ OLIY

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ustoz✍️ Bunyod Raxmanov
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πŸ‘4
π‚π‘πžπ¦πŽπŸπŸπ’πœπž
Bir necha xil usuldagi yechimlari kerakmi❓
Unda faol bo'ling, kamida 50+ πŸ‘ yig'sa, yechimlar beriladiπŸ™‚
πŸ”’πŸ”’ ta πŸ‘ bor, yana shuncha πŸ‘ yigΚ»ilsa, juda sodda yechim turlari beriladiπŸ™‚
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πŸ” πŸ” πŸ” πŸ” πŸ” πŸ” 

⚜️MILLIY SERTIFIKAT⚜️ maxsus guruhida tahlil qilinayotgan testlardan
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ustoz✍️ Bunyod Raxmanov
kanalπŸ”—
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🧠miyani charxlaymizβš”οΈ
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HNO3 ning 6 molyalli 68.9 g eritmasiga necha molyalli 250.4 g eritmasi qΓ²shilganda molyal va molyar konsentratsiyalari teng bΓ²lgan eritma (d=1.2772 g/ml) olinadi?


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ustoz
✍️ Bunyod Raxmanov
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πŸ”— @ChemOfficer
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πŸ”— @olympic_uz_ru_en
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🧠miyani charxlaymizβš”οΈ βœ”οΈjavobingizni tahlil guruhida bildiring HNO3 ning 6 molyalli 68.9 g eritmasiga necha molyalli 250.4 g eritmasi qΓ²shilganda molyal va molyar konsentratsiyalari teng bΓ²lgan eritma (d=1.2772 g/ml) olinadi? ⚜️MILLIY SERTIFIKAT⚜️ πŸ“ŽQABULGA…
πŸ‘€ yechimini kutayotganlar bormiπŸ™‹πŸ»β€β™‚οΈπŸ™‹πŸ»β€β™€οΈ
qani yechimini yozib joylagunimcha kim sodda yechim
✍️ taklif qilarkanπŸ™‚
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🧠miyani charxlaymizβš”οΈ βœ”οΈjavobingizni tahlil guruhida bildiring HNO3 ning 6 molyalli 68.9 g eritmasiga necha molyalli 250.4 g eritmasi qΓ²shilganda molyal va molyar konsentratsiyalari teng bΓ²lgan eritma (d=1.2772 g/ml) olinadi? ⚜️MILLIY SERTIFIKAT⚜️ πŸ“ŽQABULGA…
πŸ” πŸ” πŸ” πŸ” πŸ” πŸ” 

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ustoz
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kanal
πŸ”— @ChemOfficer
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πŸ‘1
πŸ…°οΈπŸ…°οΈπŸ…°οΈπŸ…°οΈ
#repetitor_1. Rasmda flyuren molekulasi ko'rsatilgan, bunda C atomlari III valentli, demak gibridlanish turi sp2.

⌨️⌨️⌨️⌨️⌨️⌨️
#repetitor_2. Assalomu alaykum ustoz, yaxshimisiz! Flyurenda IV valentli emasmi? Iltimos, aniqlik kiritib bersangiz.
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πŸ…°οΈπŸ…°οΈπŸ…°οΈπŸ…°οΈ #repetitor_1. Rasmda flyuren molekulasi ko'rsatilgan, bunda C atomlari III valentli, demak gibridlanish turi sp2. ⌨️⌨️⌨️⌨️⌨️⌨️ #repetitor_2. Assalomu alaykum ustoz, yaxshimisiz! Flyurenda IV valentli emasmi? Iltimos, aniqlik kiritib bersangiz.
πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 
Voleykum assalom. Fulleren tarkibidagi uglerod atomlari IV valentli, fulleren kovalent boğlari benzolga yaqin delokallashgan pi boğlarga ega, shu tufayli ham boğ masofalari xuddi benzoldagidek: ~1,40 Β°A β€” olti halqali, ~1,46 Β°A β€” besh halqali. Keng ommaga ilmni targ'ib qilishdan oldin "research (ilmiy tekshirish)" qilishni o'rganishsa maqsadga muvofiq bo'ladi.

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