UNIVERSAL KIMYO
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Keling!!! Kimyoni birgalikda Γ³rganamizπŸ”₯
Π”Π°Π²Π°ΠΉΡ‚Π΅!!! Π˜Π·ΡƒΡ‡Π°Π΅ΠΌ вмСстС Π₯имиюπŸ”₯
ustoz: Bunyod Raxmanov
Bog'lanish πŸ”— @ChemOfficer_bot
Bog'lanish πŸ”— @ProChem
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πŸ”’πŸ”’
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πŸ‘8
πŸ“£ Oldindan tayyorlanishni boshlaymiz
Telegram ekranni xira ko'rsatadi, yana kechqurun, shu tufayli Zoom orqali o'tamiz. Zoom dasturi borlar Zoom orqali, Zoom dasturi yo'qlar telefonida mavjud Brauzer (Chrome, Edge va h.k.) orqali kiraveradi.

⚠️Unutmang: Brauzer orqali kirganda ism so'raydi, unga ixtiyoriy ism (belgi) qo'ygach, keyin kirishga ruhsat beradi.

πŸ”—Quyida ikkita ssilka beraman, chunki Zoom ning bepul ta'rifida 40 min limitli vaqt beradi, o'chgach 2-ssilka orqali davom etib ketaveramiz va shu tariqa takrorlanadi.
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yo tovuqπŸ“
yo tuhumπŸ₯š

πŸ” πŸ” πŸŸ’πŸ” 
🌐nline dars uchun Telegramdan foydalanilsa, kechqurun sifati juda yomonlashadi, ayniqsa videodarsni telegram orqali yozib olish ham yuklansa. Zoom dasturi (ilovasi)dan foydalanilsa, ancha sifatli dars jarayonini olib borish mumkin, videoni ham sifatli yozadi. Ammo, tinglovchilarning aksari Zoom orqali darsga kirolmayapti, demakki, yo qanday kirishni bilmaydi, yoki boshqa sabab. Ya'ni, sifati past Telegram orqali tez kirishyapti, sifati yuqori Zoom orqali kirishga qiynalishyapti. Demak, Zoom dasturidan qanday foydalanish ketma-ketligini ertaga yoritib beraman. Keyin yana harakat qilib ko'ramiz Zoom orqali dars jarayonini olib borishni. Agar shunda ham ko'pchilik qiynalsa, unda majbur Telegram orqali faqat doska usulidan (ustoz xatti-xarakati ko'rinmaydi) foydalanamiz.
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Assalomu aleykum hurmatli kanal a'zolari!
Bugun asosiy vaqtimni
🌐nline darsni qaysi dastur orqali sifatli olib borish va yozib olishga sarflayman. 🌐Telegram foydalanish uchun juda qulay, ammo sifati juda yomon, πŸ”Zoom vaqtni limitlagan, ammo sifati yaxshi. Yana boshqa dastur (ilovla)lar bilan ham tanishib, qatnashuvchilar uchun eng sodda va qulay bo'lgan va eng asosiysi sifatli tasvir uzatadiganini tanlab olishga harakat qilaman. Yaxshi niyatli qadrdonlar duo qilib turarsizlar🀲

Ungacha kanal o'z faoliyatini an'anaviy davom ettirib turadiπŸ™‚
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πŸ’₯FORMAL ZARYADπŸ’₯

⚠️ "Formal zaryad" mavzusi bizga deyarli kirib kelmagani uchun, juda ko'pchilik aksari o'rganuvchilar, xatto o'rgatuvchilar ham formal zaryad (FZ) va oksidlanish daraja (OD) qiymatlarini aralashtirib yuborishadi (bu ularning kamchiligi emas albatta, kamchilik shu ilmning olib kirilmaganida). Masalan, O3 dagi O atomlarining OD qiymatlari -1, 0, +1 deb biladiganlar bor, aslida bu FZ qiymatlari, OD qiymatlari esa barchasida 0 ga teng. Shu tufayli bu mavzuni nafaqat video shaklida yoritdim, balki UNIVERSAL KIMYO kitobimga tahlillari va OD bilan solishtirishlari asosida kiritdim (kitob nomiga "universal" so'zi bekorga kiritilmagan).

πŸ—‚ UNIVERSAL KIMYO
πŸ’ UMUMIY πŸ’ ANORGANIK
πŸ’ ORGANIKπŸ’ OLIY
πŸ’» @universal_kimyo
☎️ 93-585-17-12

⚜️MILLIY SERTIFIKAT⚜️
πŸ“ŽQABULGA YOZILISHπŸ“Ž
πŸ‘¨πŸ»β€πŸ’»
@online_dars_qabul
πŸ‘©πŸ»β€πŸ’»
@qabul_online_dars
_________
ustoz
✍️ Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanal
πŸ”— @olympic_uz_ru_en
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πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 
EKVIVALENT (nazariy & amaliy)
_____________________________
ustoz
✍️ Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanal
πŸ”— @olympic_uz_ru_en
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πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 
Vant-Goff qonuni asosida
_____________________________
ustoz
✍️ Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanal
πŸ”— @olympic_uz_ru_en
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πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 
Kimyoviy reaksiyani to'g'ri ifodalay olish asosida
_____________________________
ustoz
✍️ Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanal
πŸ”— @olympic_uz_ru_en
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πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 
1️⃣ Fizikaviy xossalarni to'g'ri ifodalay olish asosida
2️⃣ Hisoblashda massa saqlanish qonuni asosida
_____________________________
ustoz
✍️ Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanal
πŸ”— @olympic_uz_ru_en
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πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 
1️⃣ VBN gibridlanish asosida
2️⃣ Organik formula yodlash asosida
3️⃣ Organik reaksiya mexanizmi asosida
_____________________________
ustoz
✍️ Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanal
πŸ”— @olympic_uz_ru_en
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πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 
1️⃣ Zichlik bo'yicha β€” o'rta darajada murakkab
2️⃣ Zichlik bo'yicha β€” og'ir darajada murakkab
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ustoz
✍️ Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanal
πŸ”— @olympic_uz_ru_en
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πŸ” πŸ”€πŸ” πŸ” πŸ” πŸ” 
1️⃣ u β€” n.a.m. o'zgarishi asosida Ar ning necha marta o'zgarishini hisoblash
2️⃣ u β€” n.a.m. o'zgarishi asosida Ar ning yangi n.a.m ni hisoblash
βœ”οΈshaxsiy keltirib chiqargan formulalarim asosidaπŸ™‚
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ustoz
✍️ Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanal
πŸ”— @olympic_uz_ru_en
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Live stream scheduled for
πŸ’™πŸ’™πŸ’™β–ΆοΈ 🌐NLAYN DARS
✈️ @ChemOfficer kanalida
πŸ”— yaqinlarimizga ulashamiz

2️⃣7️⃣
πŸ—“sentyabr kuni kimyo fani bo'yicha ⚜️Milliy Sertifikat⚜️ imtihoni bo'lib o'tadi. Shu munosabat bilan talabgorlarga ozmi-ko'pmi o'z xissamni qo'shishni maqsad qildim. 1️⃣5οΈβƒ£πŸ”£sentyabrdan boshlab yangi nashrdan chiqqan "Milliy Sertifikat β€” yozma ish topshiriqlari" to'plamini (S. Boboyev, Sh. Usmonov) tahlil qilishni boshlaymiz. Nima uchun deganda ayni ushbu qismi, ya'ni 41-, 42-, 43-yozma ishlar qismi ko'pchilikni qiynamoqda va yechmasdan tashlab ketishmoqda. Lekin ayni shu 3 ta topshiriq eng yuqori ballarni to'plashga yordam beradi. Tahlil qilish uchun sizdan albatta kuchli nazariy fundamental ilm talab qilinadi. Buning uchun sizga albatta yangi nashrdan chiqqan UNIVERSAL KIMYO (B. Raxmanov) kerak bo'ladi. Shunday ekan, tahlillarni chuqur o'zlashtirish uchun ushbu kitoblarni tezda oling va maqsadingizga tezroq yetingπŸ™‚

πŸ“ŽBUYURTMA BERISHπŸ“Ž

πŸ—‚ UNIVERSAL KIMYO
πŸ’ UMUMIY πŸ’ ANORGANIK
πŸ’ ORGANIKπŸ’ OLIY
πŸ’» @universal_kimyo
☎️ 93-585-17-12

πŸ—‚ MILLIY SERTIFIKAT
✍️ yozma ish topshiriqlari
πŸ’» @SPECTRUM_nashriyoti
☎️ +998334461122
_________________________________
ustoz
✍️ Bunyod Raxmanov
kanal
πŸ”— @ChemOfficer
kanal
πŸ”— @olympic_uz_ru_en
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πŸ”’πŸ”’
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▢️jonli 🌐nline darsga qatnasha olmadim yoki texnik sabablarga ko'ra kira olmadim deb xech siqilmangπŸ™‚ barcha tahlillar videoβ–ΆοΈΠ·Π°ΠΏΠΈΡΡŒ qilindi, hajmini kichraytirib nasib tez orada kanalga joylayman⏳

πŸ”—kanal linkini yaqinlaringizga ulashing πŸ‘‰online kursπŸ‘ˆ zero imtiohonga ozmi-ko'pmi yordamimiz tegsinπŸ™Œ chunki tahlillar har kuni bo'ladi, nasibπŸ—“
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πŸ‘6πŸ€—3