By Reheating in Rankine Power plant, mean temperature of heat addition
Anonymous Poll
10%
1 Decreases
79%
2 Increases
11%
3 Can't say
Formation of Bainite can be shown in equilibrium Iron carbon diagram having Temperature at y axis and composition at x axis?
Anonymous Poll
52%
1 True
48%
2 False
Fundamentals of Mechanical Engineering ❤️
By Reheating in Rankine Power plant, mean temperature of heat addition
The answer to this poll is
Increases-As we increase mean temperature of heat addition we reduce the temperature difference and hence inturn we reduce entropy because entropy increases for finite temp difference.
Increases-As we increase mean temperature of heat addition we reduce the temperature difference and hence inturn we reduce entropy because entropy increases for finite temp difference.
Fundamentals of Mechanical Engineering ❤️
Formation of Bainite can be shown in equilibrium Iron carbon diagram having Temperature at y axis and composition at x axis?
The answer to this poll is
False-Formation of bainite can be shown in non equilibrium diagram, or Temp-time diagram.
False-Formation of bainite can be shown in non equilibrium diagram, or Temp-time diagram.
For a given cross sectional area and young's modulus when slenderness ratio increases the buckling tendency
Anonymous Poll
48%
1 Increases
48%
2 Decreases
3%
3 Data is not sufficient
The answe to the above poll is
Increases- For a given cross section and young's modulus, buckling load and Slenderness ratio are inversely proprtional. So when slenderness ratio will increase then buckling load has to decrease which means the object will have more chance to buckle.
Increases- For a given cross section and young's modulus, buckling load and Slenderness ratio are inversely proprtional. So when slenderness ratio will increase then buckling load has to decrease which means the object will have more chance to buckle.
The diameter of laminar fluid flowing through a pipe of diameter d triples then pressure head loss will decrease by factor of
Anonymous Poll
26%
1 1/27
44%
2 1/81
18%
3 1/9
12%
4 Remains same
The answer to the above poll is
2 1/81
Hagen–Poiseuille equation gives head loss in a pipe having laminar flow. From the equation we can conclude that head loss is inversely proportional to d^4.
2 1/81
Hagen–Poiseuille equation gives head loss in a pipe having laminar flow. From the equation we can conclude that head loss is inversely proportional to d^4.
In Simplex, the condition of degeneracy will be when one or more than one basic variable should be 0.
Such that number of variables will be less than number of equations which will create Degeneracy.
#FUNDA #INDUSTRIAL
Such that number of variables will be less than number of equations which will create Degeneracy.
#FUNDA #INDUSTRIAL
P=F/A
If Area decreases Pressure will
If Area decreases Pressure will
Anonymous Poll
63%
1 Increase
22%
2 Decrease
15%
3 Cannot tell
The answer to the above poll is
2 Decreases- Pressure generally is applied by fluids, solids cannot apply pressure they induce stress always.
So, by using continuity equation and Bernoulis equation we will get that Area increases pressure increases which happens in Diffuser and vise versa in Nozzle.
#Interview #FUNDA
2 Decreases- Pressure generally is applied by fluids, solids cannot apply pressure they induce stress always.
So, by using continuity equation and Bernoulis equation we will get that Area increases pressure increases which happens in Diffuser and vise versa in Nozzle.
#Interview #FUNDA
In water delogging process at a faster rate which pump should be used
Anonymous Poll
66%
1 Centrifugal pump
34%
2 Axial Pump
The answer to the above poll is
2 Axial Pump
The diacharge of axial flow pump is more than centrifugal pumps. So we will use Axial flow pumps to delog water at a faster rate.
2 Axial Pump
The diacharge of axial flow pump is more than centrifugal pumps. So we will use Axial flow pumps to delog water at a faster rate.
To check whether there is much frictional loss through cylinder walls due to improper lubrication of an SI Engine which parameter will give the better idea
Anonymous Poll
23%
1 Break Thermal Efficiency
9%
2 Relative Efficiency
51%
3 Mechanical Efficiency
18%
4 Indicated break thermal efficiency
The answer to the above poll is
3 Mechanical Efficiency - Higher the mechanical efficiency, very less will be the frictional power. Indicated power is the power available at the piston and if the friction is high so mechanical efficiency will be very less.
3 Mechanical Efficiency - Higher the mechanical efficiency, very less will be the frictional power. Indicated power is the power available at the piston and if the friction is high so mechanical efficiency will be very less.
In Springs which side of spring has more chance to fail
Anonymous Poll
57%
1 Inner side
32%
2 Outer side
10%
3 Insufficient data
The answer to the above poll is
1 Inner side
Because both the direct shear stress and the twisting couple stress are in the same direction in inner side whereas in outer side both the stresses are in opposite direction.
So inner side of the spring is critical.
1 Inner side
Because both the direct shear stress and the twisting couple stress are in the same direction in inner side whereas in outer side both the stresses are in opposite direction.
So inner side of the spring is critical.
Which will have more power loss
Anonymous Poll
44%
1 Multi collar bearing
24%
2 Single collar bearing
32%
3 Equal in both