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๐Ÿ”ต๐Ÿ”ตHis research topics include:

โœ…Riemannian geometry
โœ…Geometric topology
โœ…Proof of the soul conjecture
โœ…Proof of the Poincarรฉ conjecture

๐Ÿ”ด๐Ÿ”ดAwards

๐Ÿ…Saint Petersburg Mathematical Society 
๐Ÿ…Prize (1991)
๐Ÿ…EMS Prize (1996), declinedโŒ
๐Ÿ…Fields Medal (2006), declinedโŒ
๐Ÿ…Millennium Prize (2010), declinedโŒ

โฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธโฌ‡๏ธ

His mathematical education continued at theLeningrad Secondary School, aspecialized school with advanced mathematics and physics programs.

๐Ÿ…1982:
as a member of theSoviet Union team competing in theInternational Mathematical Olympiad, an international competition for high school students, he won a gold medal, achieving a perfect score.

๐Ÿ…1994:
Perelman proved the soul conjecture.

๐Ÿ…2003:
he proved (confirmed in 2006)Thurston's geometrization conjecture.
This consequently solved in the affirmative thePoincarรฉ conjecture.

๐Ÿ…August 2006:
Perelman was offered theFields Medal for "his contributions to geometry and his revolutionary insights into the analytical and geometric structure of theRicci flow", but he declined the award, stating:
โญ๏ธ
I'm not interested in money or fame; I don't want to be on display like an animal in a zooโญ๏ธ

๐Ÿ…22 December 2006:
the scientific journal Science recognized Perelman's proof of the Poincarรฉ conjecture as the scientific "Breakthrough of the Year", the first such recognition in the area of mathematics.

๐Ÿ…18 March 2010:
it was announced that he had met the criteria to receive the first ClayMillennium Prize for resolution of the Poincarรฉ conjecture.

๐Ÿ…1 July 2010:
he turned down the prize of one million dollars, saying that he considered the decision of the board of CMI and the award very unfair and that his contribution to solving the Poincarรฉ conjecture was no greater than that ofRichard S. Hamilton, the mathematician who pioneered the Ricci flow with the aim of attacking the conjecture.

๐Ÿ…
He also turned down the prestigious prize of the European Mathematical Society.
๐Ÿ‘14
๐Ÿ‘‡This is problem number 29๐Ÿ‘‡

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๐Ÿ‘‡This is problem number 30๐Ÿ‘‡

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