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3.6 .. A dog running in an open field has components of velocityvx = 2.6 m>s and vy = -1.8 m>s at t1 = 10.0 s. For the timeinterval from t1 = 10.0 s to t2 = 20.0 s the average accelerationof the dog has magnitude 0.45 m>s2 and direction 31.0_ measuredfrom the +x@axis toward the +y@axis. At t2 = 20.0 s (a) what arethe x- and y-components of the dog’s velocity? (b) What are themagnitude and direction of the dog’s velocity? (c) Sketch the velocityvectors at t1 and t2. How do these two vectors differ?