√a^2+9a^2/4=a√13/2

√40*x=√26*√20+√14*√20
√40*x=√20(√26+√14)
X=√13+√7

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how many quadratic equations which are unchanged by squaring their roots are ???
1
0
2
3
4

a,b
X^2-(a+b)x+ab=0
X^2-(a^2+b^2)x+a^2b^2=0
a+b=a^2+b^2. ab=a^2b^2
ab(ab-1)=0. ab=1. ab=0
(a+b)(a+b-1)=2ab
if ab=0
a+b=0. a+b=1.
Equation. X^2=0.......1
X^2-x+0=0........2
if ab=1
a+b=2. a+b=1. a+b=3
X^2-2x+1=0.......3
x^2-x+1=0 not possible

Total 3

Total number of multiple of 10,100,1000
2000/10+200/100+2000/1000=222
Remaining numbers 101 se 199
Except 110,120,.........190 in every hundred =9*9=81
From 1001 to 1010 total 2*9+1=19
From 1011 to 1099
Number like 1020,1030,.. we have already counted 1 0 so 1 zero left
Total 89
Now number left from
1101 to. 1109
1201 to. 1209
.
..
1901. To. 1909.
Total. 9*9=81
Total. 222+81+19+89+81
=222+189+81=222+270=492

There are how many numbers from 1 to 1000 in which there is either only one 5 or only one 3 but not both together ?,

Total possibility together
305. 350. 530. 503. 035 053
Ni lena 9*6=54
But here we have take the number. 355 and 335 twice because
350 ,351, 352,....355,( ye le Liya)....
335 ko. 035 wale m aayega bha already le liye



So 54-12=42
Total number that with 3 or 5
19+19)*8=304
From 300 to 399
500 to. 599. 200
304+200-42=462

Circum centre of right angled triangle lies on hypotenuse.(y = 1)

Only option A.

A-d ,a,a+d,a+2d
A(a+d)=4
(A-d)(a+2d)=-14= 7*(-2)
Either frist term is -2 or -7
But >-3. So -2
A-d=-2
A+2d=7
D=3. A=1
-2+27=25

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Let's take base 14
Cordinate of centroid=0-5+9/3=4/3
12+0+0/3=4
Of incentre=0*14-15*5+13*9/42
=42/42=1
14*12+0/42=4
(1,4). (4/3,4)
Distance 4/3-1=1/3