Sleepy Classes IAS
Day 13 CSAT PYQ Series Today, we will be looking at a LR question. We alternate between RC, LR and Quant PYQs in this series. Try to solve it. Solutions will be provided later today.
Solution of Day 13 CSAT PYQ
Table dimensions: 6' x 10'
Blue rectangle dimensions: 2.5' x 8' (Quantity: 2)
Step 1:
Placement Constraint
The problem states each blue portion has "exactly two sides common with two edges of the table top."
This geometrically requires each blue rectangle to be placed exactly into one of the 4 corners of the table.
Step 2:
Orientation Constraint
Since the table's width is 6' and the blue rectangle's length is 8', the 8' side of the blue rectangle cannot be placed along the 6' edge.
It must be aligned along the 10' edge.
Therefore, the orientation of the blue rectangles within any chosen corner is strictly fixed.
Step 3:
Calculating Patterns
Because the table is fixed to the ground, we cannot rotate it to make patterns look identical. Every unique selection of corners creates a distinct visual pattern from above.
To find the total patterns, calculate the number of ways to choose 2 corners out of the 4 available corners:
4C2 = (4 × 3) / (2 × 1) = 6
There are 6 possible patterns.
Correct Answer:
(c) 6
Table dimensions: 6' x 10'
Blue rectangle dimensions: 2.5' x 8' (Quantity: 2)
Step 1:
Placement Constraint
The problem states each blue portion has "exactly two sides common with two edges of the table top."
This geometrically requires each blue rectangle to be placed exactly into one of the 4 corners of the table.
Step 2:
Orientation Constraint
Since the table's width is 6' and the blue rectangle's length is 8', the 8' side of the blue rectangle cannot be placed along the 6' edge.
It must be aligned along the 10' edge.
Therefore, the orientation of the blue rectangles within any chosen corner is strictly fixed.
Step 3:
Calculating Patterns
Because the table is fixed to the ground, we cannot rotate it to make patterns look identical. Every unique selection of corners creates a distinct visual pattern from above.
To find the total patterns, calculate the number of ways to choose 2 corners out of the 4 available corners:
4C2 = (4 × 3) / (2 × 1) = 6
There are 6 possible patterns.
Correct Answer:
(c) 6
👍2❤1
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Bachon..
Shekhar sir here…
July mein India mein kaafi kuchh hua
As far as I could figure out, July mein kaafi time spend ho gaya padhai se dur
Make up in August
August mein jahaan tak possible ho, cover up..
Move with a plan
And rapidly catch up
Let me know if you need any help with this
Shekhar sir here…
July mein India mein kaafi kuchh hua
As far as I could figure out, July mein kaafi time spend ho gaya padhai se dur
Make up in August
August mein jahaan tak possible ho, cover up..
Move with a plan
And rapidly catch up
Let me know if you need any help with this
❤16👍2
Hi all,
Today is Day 14 of 30
Prelims Sleepy Series 2026
All 100 questions.
30 days.
Download the PDF given below.
Today is Day 14 of 30
Prelims Sleepy Series 2026
All 100 questions.
30 days.
Download the PDF given below.
❤4👍3
With less than 20 days left for Mains 2026.
Time is precious.
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Reserve Your Seat
https://lp.sleepyclasses.com/upsc-mains-current-affairs
Time is precious.
Cover the 100 Most Important Current Affairs for UPSC Mains 2026 in Just 3 days
Join Ayush Raina Sir on the 3, 4 & 5 August 2026.
Master 12 current affairs themes mapped across all GS papers.
Get answer-ready material for UPSC Mains 2026.
Reserve Your Seat
https://lp.sleepyclasses.com/upsc-mains-current-affairs
👍2❤1
Sleepy Classes IAS
With less than 20 days left for Mains 2026. Time is precious. Cover the 100 Most Important Current Affairs for UPSC Mains 2026 in Just 3 days Join Ayush Raina Sir on the 3, 4 & 5 August 2026. Master 12 current affairs themes mapped across all GS papers.…
Given above is the PDF sample of the Answer Ready Notes that will be provided in this 3 day workshop.
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VIEW IN TELEGRAM
Hi all,
Ayush Raina Sir sent a short video message exclusively for all our Telegram Subscribers who are appearing in Mains 26.
Do check out the page here:
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Ayush Raina Sir sent a short video message exclusively for all our Telegram Subscribers who are appearing in Mains 26.
Do check out the page here:
https://lp.sleepyclasses.com/upsc-mains-current-affairs
And an extra Sample PDF below
You can use coupon code MAINS27 to get an extra 25%off
❤6👍1
Long academic article alert 🚨
We are Living in a Million Societies and Consensus now is an illusion
https://www.reddit.com/r/SocioUPSC/s/Lkge8gIN5k
(will be writing more on this subreddit 🙏)
We are Living in a Million Societies and Consensus now is an illusion
https://www.reddit.com/r/SocioUPSC/s/Lkge8gIN5k
(will be writing more on this subreddit 🙏)
❤8👍1
Doston… If you are a UPSC aspirant who could not make it through to the final list
There’s this opening exclusively for those who are there on Pratibha setu portal
Do find out
NTA hai, so thoda adventure bhi ho jayega 😃
https://nta.ac.in/Download/Notice/Notice_20260727182748.pdf
There’s this opening exclusively for those who are there on Pratibha setu portal
Do find out
NTA hai, so thoda adventure bhi ho jayega 😃
https://nta.ac.in/Download/Notice/Notice_20260727182748.pdf
❤3👍1
𝗥𝗶𝘀𝗶𝗻𝗴 𝗘𝘅𝘁𝗿𝗲𝗺𝗲 𝗪𝗲𝗮𝘁𝗵𝗲𝗿 𝗥𝗶𝘀𝗸𝘀:
India faces mounting climate threats like heatwaves, cyclones, and flash floods, with hot days increasing and extreme rain events tripling over recent decades.
𝗧𝗵𝗲 𝗟𝗶𝗺𝗶𝘁 𝗼𝗳 𝗘𝗮𝗿𝗹𝘆 𝗪𝗮𝗿𝗻𝗶𝗻𝗴𝘀:
While forecasting has improved, warnings only indicate danger without teaching people what immediate actions to take during an emergency.
𝗠𝗮𝗻𝗱𝗮𝘁𝗼𝗿𝘆 𝗦𝗲𝗮𝘀𝗼𝗻𝗮𝗹 𝗗𝗿𝗶𝗹𝗹𝘀:
Every school, college, and workplace should conduct two drills annually one before heatwaves and another before the monsoon.
𝗣𝗿𝗮𝗰𝘁𝗶𝗰𝗮𝗹 𝗗𝗶𝘀𝗮𝘀𝘁𝗲𝗿 𝗧𝗿𝗮𝗶𝗻𝗶𝗻𝗴:
Drills should focus on real-world actions, such as identifying cooled spaces for heatwaves, practicing evacuation routes, and avoiding moving floodwaters.
𝗦𝗰𝗵𝗼𝗼𝗹-𝗟𝗲𝘃𝗲𝗹 𝗘𝗱𝘂𝗰𝗮𝘁𝗶𝗼𝗻:
Disaster management must become a practical part of primary education to teach children local hazards, safe routes, and basic first aid.
𝗖𝗼𝗺𝗺𝘂𝗻𝗶𝘁𝘆 𝗦𝗮𝗳𝗲𝘁𝘆 𝗣𝗼𝗶𝗻𝘁𝘀: Every panchayat and urban ward should designate an accessible local safety point equipped with water, first aid.
India faces mounting climate threats like heatwaves, cyclones, and flash floods, with hot days increasing and extreme rain events tripling over recent decades.
𝗧𝗵𝗲 𝗟𝗶𝗺𝗶𝘁 𝗼𝗳 𝗘𝗮𝗿𝗹𝘆 𝗪𝗮𝗿𝗻𝗶𝗻𝗴𝘀:
While forecasting has improved, warnings only indicate danger without teaching people what immediate actions to take during an emergency.
𝗠𝗮𝗻𝗱𝗮𝘁𝗼𝗿𝘆 𝗦𝗲𝗮𝘀𝗼𝗻𝗮𝗹 𝗗𝗿𝗶𝗹𝗹𝘀:
Every school, college, and workplace should conduct two drills annually one before heatwaves and another before the monsoon.
𝗣𝗿𝗮𝗰𝘁𝗶𝗰𝗮𝗹 𝗗𝗶𝘀𝗮𝘀𝘁𝗲𝗿 𝗧𝗿𝗮𝗶𝗻𝗶𝗻𝗴:
Drills should focus on real-world actions, such as identifying cooled spaces for heatwaves, practicing evacuation routes, and avoiding moving floodwaters.
𝗦𝗰𝗵𝗼𝗼𝗹-𝗟𝗲𝘃𝗲𝗹 𝗘𝗱𝘂𝗰𝗮𝘁𝗶𝗼𝗻:
Disaster management must become a practical part of primary education to teach children local hazards, safe routes, and basic first aid.
𝗖𝗼𝗺𝗺𝘂𝗻𝗶𝘁𝘆 𝗦𝗮𝗳𝗲𝘁𝘆 𝗣𝗼𝗶𝗻𝘁𝘀: Every panchayat and urban ward should designate an accessible local safety point equipped with water, first aid.
👍1
Hi all,
Today is Day 15 of 30
Prelims Sleepy Series 2026
All 100 questions.
30 days.
Download the PDF given below.
Today is Day 15 of 30
Prelims Sleepy Series 2026
All 100 questions.
30 days.
Download the PDF given below.
👍1
Sleepy Classes IAS
Day 14 CSAT PYQ Series Today, we will be looking at a Maths question. We alternate between RC, LR and Quant PYQs in this series. Try to solve it. Solutions will be provided later today.
Step 1:
Write the equation for the successive changes.
An increase of k% means multiplying by (1 + k/100).
A decrease of k% means multiplying by (1 - k/100).
q = p * (1 + k/100) * (1 - k/100) * (1 + k/100) * (1 - k/100)
Step 2:
Group and simplify the terms.
Using the algebra rule (a + b)(a - b) = a^2 - b^2
We can simplify each increase/decrease pair:
(1 + k/100) * (1 - k/100) = 1 - (k^2 / 10000)
Since 10000 is 10^4, we can rewrite this fraction as:
(10^4 - k^2) / 10^4
Step 3:
Combine both pairs.
Because the increase/decrease cycle happens twice,
we multiply the simplified pair by itself:
q = p * [ (10^4 - k^2) / 10^4 ] * [ (10^4 - k^2) / 10^4 ]
q = p * [ (10^4 - k^2)^2 / (10^4)^2 ]
Step 4:
Rearrange the equation.
Multiply the denominators:
(10^4)^2 = 10^8
Substitute that back in:
q = p * [ (10^4 - k^2)^2 / 10^8 ]
Multiply both sides by 10^8 to clear the fraction:
q * 10^8 = p(10^4 - k^2)^2
Conclusion:
This matches option (a): p(10^4 - k^2)^2 = q * 10^8
Write the equation for the successive changes.
An increase of k% means multiplying by (1 + k/100).
A decrease of k% means multiplying by (1 - k/100).
q = p * (1 + k/100) * (1 - k/100) * (1 + k/100) * (1 - k/100)
Step 2:
Group and simplify the terms.
Using the algebra rule (a + b)(a - b) = a^2 - b^2
We can simplify each increase/decrease pair:
(1 + k/100) * (1 - k/100) = 1 - (k^2 / 10000)
Since 10000 is 10^4, we can rewrite this fraction as:
(10^4 - k^2) / 10^4
Step 3:
Combine both pairs.
Because the increase/decrease cycle happens twice,
we multiply the simplified pair by itself:
q = p * [ (10^4 - k^2) / 10^4 ] * [ (10^4 - k^2) / 10^4 ]
q = p * [ (10^4 - k^2)^2 / (10^4)^2 ]
Step 4:
Rearrange the equation.
Multiply the denominators:
(10^4)^2 = 10^8
Substitute that back in:
q = p * [ (10^4 - k^2)^2 / 10^8 ]
Multiply both sides by 10^8 to clear the fraction:
q * 10^8 = p(10^4 - k^2)^2
Conclusion:
This matches option (a): p(10^4 - k^2)^2 = q * 10^8
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