UNIVERSAL KIMYO
5.14K subscribers
7.37K photos
1.36K videos
349 files
1.62K links
Keling!!! Kimyoni birgalikda รณrganamiz๐Ÿ”ฅ
ะ”ะฐะฒะฐะนั‚ะต!!! ะ˜ะทัƒั‡ะฐะตะผ ะฒะผะตัั‚ะต ะฅะธะผะธัŽ๐Ÿ”ฅ
ustoz: Bunyod Raxmanov
Bog'lanish ๐Ÿ”— @ChemOfficer_bot
Bog'lanish ๐Ÿ”— @ProChem
Download Telegram
๐Ÿ’ฌtakrorlab olamiz โ€” zero ilmni mustahkamlashning eng optimal yechimi takrorlashdir๐Ÿ™‚

๐Ÿง miyani charxlaymizโš”๏ธ
โœ”๏ธ javobingizni tahlil guruhida bildiring

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ”— @ChemOfficer
kanal
๐Ÿ”— @olympic_uz_ru_en
Please open Telegram to view this post
VIEW IN TELEGRAM
โค1
๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” 

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ”— @ChemOfficer
kanal
๐Ÿ”— @olympic_uz_ru_en
Please open Telegram to view this post
VIEW IN TELEGRAM
โค2๐Ÿ‘2๐Ÿ”ฅ2
Nisbiy atom massalarni topishda tritiy izotopininng 2/5 qismi olinsa, uglerod elementining massasi nechiga teng bo'lar ediโ“
Anonymous Quiz
15%
6
33%
8
21%
9
31%
10
Quyidagi qaysi nitratlar parchalanganda gazlar aralashmasi hosil bo'lmaydi?
1) KNO3; 2) Cu(NO3)2; 3) Mn(NO3)2; 4) LiNO3; 5) Hg(NO3)2; 6) HgNO3; 7) NaNO3; 8) Mg(NO3)2
Anonymous Quiz
43%
1,4,7,8
16%
2,4,5,6
31%
1,3,6,7
9%
2,3,5,8
โ€‹#ilmiy_baxs
Ikkita idishda bir xil
kons.li NaOH eritmalari bor. Ularning har biriga ekvimolyar (NaOH mol miqdoriga teng) miqdorda CO2 va SO2 gazlari alohida bo'ktirildi. Reaksiya to'liq reaksiyaga kirishgan bo'lsa va idishlarga lakmus eritmasidan solinsa, har bir idishda qanday rang hosil bo'ladi?

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ“ข @ChemOfficer
kanal
๐Ÿ“ข
@olympic_uz_ru_en
ChemOffice
โ€‹#ilmiy_baxs Ikkita idishda bir xil kons.li NaOH eritmalari bor. Ularning har biriga ekvimolyar (NaOH mol miqdoriga teng) miqdorda CO2 va SO2 gazlari alohida bo'ktirildi. Reaksiya to'liq reaksiyaga kirishgan bo'lsa va idishlarga lakmus eritmasidan solinsaโ€ฆ
๐ŸŽฎilmiy tahliliy izohini kutayotganlar nechtamiz๐Ÿ™‹๐Ÿปโ€โ™‚๐Ÿ™‹๐Ÿปโ€โ™€๐Ÿ™‹๐Ÿป

๐Ÿ”ฅqani-qani faol bรฒlamiz๐Ÿ”ฅ
oliy kimyo darajasidagi ilmlarni tahlil qilib berayotgan ustoz mehnatini โค๏ธ๐Ÿ”ฅ๐Ÿ‘ bosib qรฒllab-quvvatlaymiz
๐Ÿ™‚

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ”— @ChemOfficer
kanal
๐Ÿ”— @olympic_uz_ru_en
Please open Telegram to view this post
VIEW IN TELEGRAM
๐Ÿ‘5โค2๐Ÿ”ฅ2
๐Ÿ” ๐Ÿ”ค๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” 
Ishqor bilan gazlar ekvimolyar (teng mol miqdor) nisbatda reaksiyasi natijasida nordon tuzlar hosil bo'ladi:

SO2 + NaOH = NaHSO3

CO2 + NaOH = NaHCO3

Hosil bo'lgan NaHSO3 eritmasi lakmus rangini qizilga, NaHCO3 eritmasi esa ko'k rangga bo'yaydi.

ilmiy izoh
: tuz tarkibida H borligi uchun nordon (ะบะธัะปั‹ะน) tuz deb nom berganmiz, go'yoki bunday tuzlar eritmasi tabiati doimo kislotali tabiatga (pH<7) ega sifatida qaralganday. Ammo, ilmiy tadqiqotlar shuni ko'rsatdiki, nordon tuzlarning barchasi kislotali tabiatga ega emas. Sababi, bunday tuzlarda bir vaqtning o'zida 2 xil jarayon kuzatiladi, ya'ni dissotsilanish va gidroliz:

HX(-) <โ€”> H(+) + X(2-) Km1

HX(-) + H2O <โ€”> H2X + OH(-) Km2

Bu jarayonlar qaytar jarayonlar (kimyoviy muvozanat) bo'lib, eritma muhitining tabiati Km qiymatiga bog'liq bo'ladi: Km1>Km2 kislotali; Km1<Km2 asosli.

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ”— @ChemOfficer
kanal
๐Ÿ”— @olympic_uz_ru_en
Please open Telegram to view this post
VIEW IN TELEGRAM
๐Ÿ‘2
Na2HPO4 ๐Ÿ˜Ž
Anonymous Quiz
50%
Asosli
42%
Kislotali
5%
Neytral
4%
Amfoter
NaH2PO4 ๐Ÿ˜Ž
Anonymous Quiz
54%
Kislotali
27%
Asosli
14%
Neytral
6%
Amfoter
#ilmiy_fakt๐Ÿ“š

โค๏ธโค๏ธโค๏ธ
Nega eritmada muhit har xil โ€” ya'ni NaH2PO4 kislotali, Na2HPO4 esa aksincha asosli?

๐Ÿ’š๐Ÿ’š๐Ÿ’š
Eritma muhitida mazkur kuchsiz kislota qoldiqlari ikki yo'nalishda:
1) gidroliz konstantasi
2) dissotsioanish konstantasi
natijasida qayta ionlar taqsimoti vujudga keladi. Km asosida esa muhit (pH) kelib chiqadi. Jumladan:

โ–ถ๏ธNaH2PO4
1) H2PO4(-) + H2O = H3PO4 + OH-
Km1=1,4*10(-12)
2) H2PO4(-) = HPO4(2-) + H+
Km2=6,2*10(-8)

Km1<Km2, xulosa: muhit kislotali

โ–ถ๏ธNa2HPO4
1) HPO4(2-) + H2O = H2PO4(-) + OH-
Km1=1,6*10(-7)
2) HPO4(2-) = PO4(3-) + H+
Km2=5,0*10(-13)

Km1>Km2, xulosa: muhit asosli
(ustoz
โœ๏ธ Bunyod Raxmanov)

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ”— @ChemOfficer
kanal
๐Ÿ”— @olympic_uz_ru_en
Please open Telegram to view this post
VIEW IN TELEGRAM
๐Ÿ”ปqani kimda javob bor๐Ÿ”ป
โœ”๏ธ javobingizni tahlil guruhida bildiring

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ”— @ChemOfficer
kanal
๐Ÿ”— @olympic_uz_ru_en
Please open Telegram to view this post
VIEW IN TELEGRAM
๐‚๐ก๐ž๐ฆ๐Ž๐Ÿ๐Ÿ๐ข๐œ๐ž
๐Ÿ”ปqani kimda javob bor๐Ÿ”ป โœ”๏ธ javobingizni tahlil guruhida bildiring ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov kanal๐Ÿ”— @ChemOfficer kanal๐Ÿ”— @olympic_uz_ru_en
๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” 

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ”— @ChemOfficer
kanal
๐Ÿ”— @olympic_uz_ru_en
Please open Telegram to view this post
VIEW IN TELEGRAM
๐Ÿ”ปqani kimda yechim bor๐Ÿ”ป
โœ”๏ธ javobingizni tahlil guruhida bildiring

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ”— @ChemOfficer
kanal
๐Ÿ”— @olympic_uz_ru_en
Please open Telegram to view this post
VIEW IN TELEGRAM
๐‚๐ก๐ž๐ฆ๐Ž๐Ÿ๐Ÿ๐ข๐œ๐ž
๐Ÿ”ปqani kimda yechim bor๐Ÿ”ป โœ”๏ธ javobingizni tahlil guruhida bildiring ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov kanal๐Ÿ”— @ChemOfficer kanal๐Ÿ”— @olympic_uz_ru_en
๐Ÿ–ฅbu aslida juda qiziq masala, ya'ni miya๐Ÿง  faoliyatini charxlaydiganโš”, qani kim tahlil guruhida yechim๐Ÿ“ beradi

โœ”๏ธtahlingizni muhokama guruhida bildiring
Please open Telegram to view this post
VIEW IN TELEGRAM
๐‚๐ก๐ž๐ฆ๐Ž๐Ÿ๐Ÿ๐ข๐œ๐ž
๐Ÿ”ปqani kimda yechim bor๐Ÿ”ป โœ”๏ธ javobingizni tahlil guruhida bildiring ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov kanal๐Ÿ”— @ChemOfficer kanal๐Ÿ”— @olympic_uz_ru_en
๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” ๐Ÿ” 

ustoz๐Ÿ‘จ๐Ÿปโ€๐Ÿซ Bunyod Raxmanov
kanal
๐Ÿ”— @ChemOfficer
kanal
๐Ÿ”— @olympic_uz_ru_en
Please open Telegram to view this post
VIEW IN TELEGRAM