1, #include <iostream>
using namespace std;

int main()
{
const int i = 20;
const int* const ptr = &i;
(*ptr)++;
int j = 15;
ptr = &j;
cout << i;
return 0;
}
Options:
a. 20
b. 21
c. 15
d. Compile error

3. What will be the output of the following program?

#include <iostream>
using namespace std;
int main()
{
int num[5];
int* p;
p = num;
*p = 10;
p++;
*p = 20;
p = &num[2];
*p = 30;
p = num + 3;
*p = 40;
p = num;
*(p + 4) = 50;
for (int i = 0; i < 5; i++)
cout << num[i] << ", ";
return 0;
}
Options:
a. 10, 20, 30, 40, 50
b. 10, 20, 30, 40, 50,
c. compile error
d. runtime error

4. What will be the output of the following program?

#include <iostream>
using namespace std;
int main()
{
int arr[] = { 4, 5, 6, 7 };
int* p = (arr + 1);
cout << *arr + 10;
return 0;
}
Options:
a. 12
b. 15
c. 14
d. error

5 What would be printed from the following C++ program?

#include <iostream>
using namespace std;
int main()
{
int x[5] = { 1, 2, 3, 4, 5 };
// p points to array x
int* p = x;
int i;
// exchange values using pointer
for (i = 0; i < 2; i++) {
int temp = *(p + i);
*(p + i) = *(p + 4 - i);
*(p + 4 - i) = temp;
}
// output the array x
for (i = 0; i < 5; i++)
cout << x[i] << " ";
return 0;
}
a) 5 4 3 2 1
b) 1 2 3 4 5
c)Address of the elements
d) Can’t say

6. What will be the output of the following program?

#include <iostream>
using namespace std;

int main()
{
int a = 32, *ptr = &a;
char ch = 'A', &cho = ch;

cho += a;
*ptr += ch;
cout << a << ", " << ch << endl;
return 0;
}
Options:
a. 32, A
b. 32, a
c. 129, a
d. 129, A

7,What would be printed from the following C++ program?

#include <iostream>
#include <stdlib.h>
using namespace std;
int main()
{
float x = 5.999;
float* y, *z;
y = &x;
z = y;
cout << x << ", " << *(&x) << ", " << *y << ", " << *z << "\n";
return 0;
}
a) 5.999, 5.999, 5.999, 5.999
b) 5.999, 5.9, 5.000, 5.900
c) Address of the elements
d) compilation error

8 What would be printed from the following C++ program?

#include <iostream>
using namespace std;

int main()
{
int track[] = { 10, 20, 30, 40 }, *striker;

striker = track;
track[1] += 30;
cout << "Striker>" << *striker << " ";
*striker -= 10;
striker++;
cout << "Next@" << *striker << " ";
striker += 2;
cout << "Last@" << *striker << " ";
cout << "Reset To" << track[0] << " ";

return 0;
}
a) 10, 20, 30, 40
b) Striker>10 Next@50 Last@40 Reset To0
c) Striker>10 Next@40 Last@50 Reset To0
d) Striker> Next@ Last@ Reset To

10 - What is the output of the following program?

#include<iostream>

using namespace std;
main() {
char s[] = "Fine";
*s = 'N';

cout<<s<<endl;
}
A - Fine

B - Nine

C - Compile error

D - Runtime error

2 What is the output of this program?

#include <iostream>
using namespace std;
void copy (int& a, int& b, int& c)
{
a *= 2;
b *= 2;
c *= 2;
}
int main ()
{
int x = 1, y = 3, z = 7;
copy (x, y, z);
cout << "x =" << x << ", y =" << y << ", z =" << z;
return 0;
}
a) 2 5 10👆
b) 2 4 5✌
c) 2 6 14👌
d) none of the mentioned👍

3😕😕 #include <iostream>
using namespace std;
void square (int *x)
{
*x = (*x + 1) * (*x);
}
int main ( )
{
int num = 10;
square(&num);
cout << num;
return 0;
}
a) 100
👆
b) compile time error
✌
c) 144
👌
d) 110👍

————————————————
| C++ Data Structure Exercise 2 |
————————————————
Question. Define a function which increments each elements of the array by 2.

(N.B. The code for the above question and answer posted in picture, now on this post in plaintext)
————————————————
#include <iostream>
using namespace std;
void numinc(int x, int *nums)
{
for(int i=0; i<x; i++){
*nums += 2;
cout<<*nums<<"\n";
nums++;
}
}
int main(){
int num[5]={3,4,5,7,11};
numinc (5, num);
return 0;
}

AI Programming @freecodecs
Have a Lit🔥 Practice Folks 🙌🏽

Infix to Postfix & Evaluate Using Stack C++
———————————————
Implementation of infix equation/expression to postfix expression converter and evaluator by using stack data structure method.

(N.B. We use stack class from library by calling #include <stack>, which is the same as doing inside our project by declaring function called pop & push.)
————————————————

AI Programming @freecodecs
Have a Lit🔥 Practice Folks 🙌🏽